Find the difference

Find the difference

 

 

Answer: 
There are ten differences in total.
1) Spot the extra bird.
2) See the direction of the paper plan.
3) Notice the amount of white flowers.
4) Count the number of snails. One is missing.
5) Count the number of butterflies. There is an extra.
6) Count the number of plants. There is an extra.
7) Count the number of apples. One is missing.
8) See the dots on the bow that belongs to the girl.
9) One less paper plane on the ground.
10) Notice the shoes of girl. They are plain white.

Trick Math Problem

There is a jar in which there are two types of candies – 20 blueberry and 16 strawberry. You perform the following steps:
1) You take out two candies.
2) If the two candies are of same flavor, you add a blueberry one otherwise, you add the strawberry one.
You repeat these two steps till there is just one candy remaining in the jar. Which flavored candy will be left?
Also, if you began with 100 blueberry candies and 93 strawberry candies, which flavor would have been the last one to remain?

Answer:
Let us suppose that there are x blueberry candies and y strawberry candies. While removing the candies, there can be three possibilities:
1) 2 blueberry candies. In this case, you will replace one blueberry candy and so the jar will have x+1 blueberry and y-2 strawberry candies.
2) 2 strawberry candies. In this case, you will replace 1 blueberry candy and so the jar will have x-1 blueberry candies and y strawberry candies.
3) 1 blueberry and 1 strawberry. In this case, you will replace a strawberry candy and so the jar will have x-1 blueberry candies and y strawberry candies.
In this way at each step, we are either removing a blueberry candy or replacing 2 strawberry candies by 1 blueberry candy irreversibly till there is only one candy left. Thus each strawberry candy is equivalent to 2 blueberry candies.
Therefore, if there are odd number of strawberry candies, the last candy will be strawberry and if there are even number of strawberry candies, the last one will be a blueberry one.

What i am Riddle

I'm heavy but not backwards.

What am I?

Answer
The word 'ton', spelled backwards it is 'not'.

What i AM

Weight in my stomach,
trees on my back,
nails in my ribs,
it's feet I lack.

What am I?

Answer
A ship.

Kids riddle

What two things can you never eat for breakfast?

Answer
Lunch and dinner!

Kids Riddle

I have all of your knowledge but could fit in your hands.

What am I?

Answer
Your brain.

What am I

I am a digit, but two of the ten.
Two of me make a promise.

What am I?

Answer 
The pinky or little finger.

Very Hard Maths Logic Question

There is a jar in which there are two types of candies – 20 blueberry and 16 strawberry. You perform the following steps:
1) You take out two candies.
2) If the two candies are of same flavor, you add a blueberry one otherwise, you add the strawberry one.
You repeat these two steps till there is just one candy remaining in the jar. Which flavored candy will be left?
Also, if you began with 100 blueberry candies and 93 strawberry candies, which flavor would have been the last one to remain ?

Answer:
Let us suppose that there are x blueberry candies and y strawberry candies. While removing the candies, there can be three possibilities:
1) 2 blueberry candies. In this case, you will replace one blueberry candy and so the jar will have x+1 blueberry and y-2 strawberry candies.
2) 2 strawberry candies. In this case, you will replace 1 blueberry candy and so the jar will have x-1 blueberry candies and y strawberry candies.
3) 1 blueberry and 1 strawberry. In this case, you will replace a strawberry candy and so the jar will have x-1 blueberry candies and y strawberry candies.
In this way at each step, we are either removing a blueberry candy or replacing 2 strawberry candies by 1 blueberry candy irreversibly till there is only one candy left. Thus each strawberry candy is equivalent to 2 blueberry candies.
Therefore, if there are odd number of strawberry candies, the last candy will be strawberry and if there are even number of strawberry candies, the last one will be a blueberry one.

Maths Problem

There has been a house on fire. The fireman is now standing in the middle rung of the ladder and trying to extinguish the fire. He climbs 6 rungs more but the heat and deadly flames make him climb down 10 rungs. When the fire is settling gradually, he climbs 18 rungs and reaches the top of the ladder for better access to the house.
Calculate the number of rungs in the ladder ?

Answer:

29 rungs
Suppose he is standing on m at first which is the middle rung.
He climbs 6 rungs which makes his position to be m+6.
He climbs down ten rungs which makes his position to be (m+6-10) = m-4
He climbs 18 rungs to reach the top t which makes his position (m-4+18) = m+14
Now, m+14 = t
Which means there are 14 rungs above the middle rung and 14 rungs below the middle rung. Counting the middle rung as well, it makes a total of 29 rungs

Infosys Interview Puzzle

The king of Octopuses has servants who have six, seven or eight legs. The distinguishing characteristics of the servants is that the one with seven legs always lie but the one with either six or eight legs speak the truth always.

On a certain night, four servants meet and converse:
The black one says, 'We have 28 legs altogether.'
The green one says, 'We have 27 legs altogether.'
The yellow one says, 'We have 26 legs altogether.'
The red one says, 'We have 25 legs altogether.'

Can you identify the color of the servant who is speaking the truth?


Answer: 

The green servant is telling the truth.
To prove it, let us first assume that one of them is telling the truth. It is obvious that three of the four servants are lying as they are disagreeing with each other.
Suppose if the black servant is telling the truth. In that case, the black one is having either 6 or 8 legs. And each of the other octopus is lying will then have 7 legs. In this case, the total number of legs will be 6 + 7 + 7 + 7 = 27 legs or 8 + 7 + 7 + 7 = 29 legs. But the black servant said that they have 28 legs all together. Thus he is lying.
Now follow the same logic with the remaining three servants as well assuming all of them truthful one by one. You will realize that only the Green octopus is telling the truth